-[x-(4x+2)]=1-(3x+8)

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Solution for -[x-(4x+2)]=1-(3x+8) equation:


Simplifying
-1[x + -1(4x + 2)] = 1 + -1(3x + 8)

Reorder the terms:
-1[x + -1(2 + 4x)] = 1 + -1(3x + 8)
-1[x + (2 * -1 + 4x * -1)] = 1 + -1(3x + 8)
-1[x + (-2 + -4x)] = 1 + -1(3x + 8)

Reorder the terms:
-1[-2 + x + -4x] = 1 + -1(3x + 8)

Combine like terms: x + -4x = -3x
-1[-2 + -3x] = 1 + -1(3x + 8)
[-2 * -1 + -3x * -1] = 1 + -1(3x + 8)
[2 + 3x] = 1 + -1(3x + 8)

Reorder the terms:
2 + 3x = 1 + -1(8 + 3x)
2 + 3x = 1 + (8 * -1 + 3x * -1)
2 + 3x = 1 + (-8 + -3x)

Combine like terms: 1 + -8 = -7
2 + 3x = -7 + -3x

Solving
2 + 3x = -7 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
2 + 3x + 3x = -7 + -3x + 3x

Combine like terms: 3x + 3x = 6x
2 + 6x = -7 + -3x + 3x

Combine like terms: -3x + 3x = 0
2 + 6x = -7 + 0
2 + 6x = -7

Add '-2' to each side of the equation.
2 + -2 + 6x = -7 + -2

Combine like terms: 2 + -2 = 0
0 + 6x = -7 + -2
6x = -7 + -2

Combine like terms: -7 + -2 = -9
6x = -9

Divide each side by '6'.
x = -1.5

Simplifying
x = -1.5

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